All categories

3 years ago

Please help with the main question in the middle pleaseeee

Mathematics

2 answers:

valina [46]3 years ago

6 0

Answer:

my addvice to you is ask your parent or teatch im sure they could give you a clou!

Step-by-step explanation:

Roman55 [17]3 years ago

3 0

Answer:

3x^2 - 5x + 1 (Option A).

Step-by-step explanation:

The a b and c in the formula relate to the letters in ax^2 + bx + c.

Comparing the 2 formula on the first line of the question:-

We see that b = -5 , a = 3 and c = 1.

So its 3x^2 - 5x + 1 (Option A).

You might be interested in

Simplify: - 3/2(4x + 3)

Korolek [52]

1) -3/2 × 4x = -6x
2) -3/2 × 3 = -9/2

Answer: -6x−9/2

3 0

3 years ago

Y = -x + 3<br> y = 2x + 6

Andrei [34K]

Answer:

y=4

x=-1

Step-by-step explanation:

replace y

2x+6=-x+3

3x=-3

x=-1

y=2x+6

y=2(-1)+6

y=-2+6

y=4

8 0

3 years ago

How to find area and perimeter HELP

denis23 [38]

Area : height x width
perimeter : 2(length + width)

5 0

3 years ago

Read 2 more answers

Write root 3 x root 6 in the form b root 2 where b is an integer

Galina-37 [17]

Answer:

$\sqrt{3}\cdot\sqrt{6}=3\cdot\sqrt{2}$

Step-by-step explanation:

<u>Radicals</u>

We have the expression:

$\sqrt{3}\cdot\sqrt{6}$

Since 6=2*3, it can be rewritten as:

$\sqrt{3}\cdot\sqrt{6}=\sqrt{3}\cdot\sqrt{2}\cdot\sqrt{3}$

Joining like radicals:

$\sqrt{3}\cdot\sqrt{6}=\sqrt{3}\cdot\sqrt{3}\cdot\sqrt{2}$

$\sqrt{3}\cdot\sqrt{6}=\sqrt{9}\cdot\sqrt{2}$

$\boxed{\sqrt{3}\cdot\sqrt{6}=3\cdot\sqrt{2}}$

This is the required form with b=2

3 0

3 years ago

John takes out a personal loan for $5,000 at an annual interest rate 7.5%, compounded monthly. He plans to pay off the loan (inc

myrzilka [38]

Answer:

155.53

Step-by-step explanation:

I know where this question is from hahaha

6 0

3 years ago