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4 years ago

Which equation represents the horizontal line passing through (-1,2)

Mathematics

1 answer:

Lunna [17]4 years ago

4 0

Answer:

y = 2

Step-by-step explanation:

When line is horizontal, all points on this line have the same value of y.

In this case , all points have to have y = 2.

y = 2, is an equation of horizontal line.

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elena55 [62]

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3 years ago

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A slice is made perpendicular to the base of a right rectangular prism as shown. What is the area of the resulting two-dimension

Yuki888 [10]

Answer:

225 i think

Step-by-step explanation:

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3 years ago

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Help please……..??.?.?.?.?.?

aleksklad [387]

9514 1404 393

Answer:

c) 16,500 m³

d) 277,088 mm³

a) V = LWH

b) V = πr²h

Step-by-step explanation:

The relevant volume formulas are ...

rectangular pyramid: V = 1/3LWH
cylinder: V = πr²h
rectangular prism: V = LWH

13c. The pyramid formula above tells us the volume is ...

V = 1/3(60 m)(15 m)(55 m) = 16,500 m³

13d. The cylinder formula above tells us the volume is ...

V = π(35 mm)²(72 mm) ≈ 277,088 mm³ ≈ 277 mL

14a. The shape appears to be a rectangular prism, so its volume is given by the formula ...

V = LWH . . . . . where L, W, H represent the length, width, and height

14b. The volume of a cylinder is given by the formula ...

V = πr²h . . . . . where r, h represent the radius and height (length)

7 0

3 years ago

What is the length of MN

NNADVOKAT [17]

Answer:

value of x = 5

Step-by-step explanation:

Given:

∠L = ∠n

So,

ML = MN

So,

3x = x + 10

2x = 10

x = 5

value of x = 5

8 0

3 years ago

Find the average velocity of the function over the given interval.

snow_lady [41]

Answer:

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

Average velocity = $\frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx$

= $\frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx$

now integrating

= $\frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )$

= $\frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}$

= $\frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))$

by using formulas

log a-log b = log(a/b)

on simplification , we get

= $\frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)$

= $log(\frac{7}{4} ) -2$

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

6 0

3 years ago