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shtirl [24]
3 years ago
7

Click and drag like terms onto each other to simplify fully -2x+1+7x-3y

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0
After it is fully simplified, it will be 5x+1-3y
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Simplify the following expression, if you can see the picture the expression is as follows:
Kobotan [32]
\sqrt{40}=2 \sqrt{10} and \sqrt{90} = 3\sqrt{10}, so we have \sqrt{10}(2-1+3). which is 4 \sqrt{10}.
8 0
3 years ago
Hamish and hairy work as plumbers. Harry earns a dollar more than 5/4 The amount Hamish orange per hour. The amount Harry earns
Mnenie [13.5K]

Answer:

Harry earns 26 and Hamish earns 20

Step-by-step explanation:

The computation of the amount earned by each one of them is shown below:

Let us assume the hairy be Y

And, the Hamish be M

It is given that Harry earns a dollar i.e more than 5/4

And, it is $2 less than  7/5

So, the equation would be

y = 1.25m + 1  ...........................(i)

And,

y= 1.4m -2  .............................(ii)

Now equal both the equations

1.25m + 1 = 1.4m - 2

3 = 0.15m

So, m = 20

Now put the values of m in any of the above equation to find out the value of Y

Y = 1.25m + 1

= 1.25 (20) + 1

= 26

6 0
3 years ago
Finding the Sum of a System of Equations
s344n2d4d5 [400]
The Answer is : -3y = 3
4 0
4 years ago
PLEASE HELP I GIVE THANKS
drek231 [11]
A, C, And D

Could be these answers...
7 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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