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bija089 [108]
3 years ago
10

Finding the Sum of a System of Equations

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
4 0
The Answer is : -3y = 3
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Write the equation of a line that is perpendicular to y=-2/7x+9 and passes through the point (4,-6)
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This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20. 
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What is the greatest number which can be made using each of the digits 5,3,1,4,7?
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3 years ago
g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
3 years ago
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