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Lorico [155]
3 years ago
7

Help plz i will make u a brainllest 24.Can you use the SSS Postulate or the SAS Postulate to prove abd=dca? 26 28

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:  24) C. SSS only

               26) D. DH = HF

<u>Step-by-step explanation:</u>

24.

<u>Statement</u>                    <u>Reason</u>

1. BD = CA                    1. Given

2. AB = CD                  2. Given

3. AD = AD                  3. Reflexive Property

4. ΔABD = ΔDCA        4. SSS Congruency Theorem

<em>We have no information about the angles so cannot use SAS Theorem.</em>

26.  G H F

      E H D

Line up the letters to find the congruent sides:

⇒  GH = EH

    HF = HD

     GF = ED

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Define the random variables X and X in words. X is the amount of time an individual waits at the courthouse to be called for ser
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<u>Question</u>

Suppose that a committee is studying whether or not there is excessive time waste in our judicial system. It is interested in the mean amount of time individuals spend at the courthouse waiting to be called for jury duty. The committee randomly surveyed 81 people who recently served as jurors. The sample mean wait time was 4 hours with a sample standard deviation of 1.2 hours. Define the random variables X and \bar{X} in words.

Answer:

(B)

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  • \bar{X}  is the mean wait time for a sample of individuals.

Step-by-step explanation:

The random variable X is the amount of time for which each of the prospective juror waits at the courthouse before being called for service.

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Graph the data in the table. Which kind of function best models the data? Write an equation to model the data. quadratic; y = 2.
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Step-by-step explanation:

x               -2              -1                 0                    1                   2

y               10            2.5                0                  2.5                3.0

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d_3=y_4-y_3

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d_4=y_5-y_4

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2nd difference,

x_1=d_2-d_1

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Since 2nd difference is common, given table represents a quadratic equation.

Let the equation is,

y = ax²+ bx + c

For a point (0, 0) passing through the quadratic equation,

0 = c

Therefore, quadratic equation is y = ax² + bx

Since ordered pair (-1, 2.5) passes through the graph of the function,

2.5 = a(-1)² + b(-1)

a - b = 2.5 ------(1)

For another point (1, 2.5)

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By adding equations (1) and (2),

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and from equation (2)→ y = 0

Therefore, equation of the quadratic function given in the table is y = 2.5x²

Option (1) is the answer.

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