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Alex
3 years ago
5

6. What is the answer to this question

Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0

D is the answer my friend

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Which of the following can be used to prove that the slope of a line is the same between any two points that lie on a line? the
OverLord2011 [107]

Answer:

the hypotenuse of similar right triangles


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3 years ago
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How do i solve this?
Leni [432]

Answer: this is hard I hate math sorry

Step-by-step explanation:

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3 0
3 years ago
Which expression is equivalent to (s - 12) / 2
lara31 [8.8K]

Answer:

s/2-6

Step-by-step explanation:

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3 0
3 years ago
Plz help i need helppppppp
Goshia [24]

Answer:

1) 36

b) 5

c) 3.0

Step-by-step explanation:

1) The recursive formula that defines the given sequence is

a_1=12 \\  a_n=a_{n-1}+4.

That means we keep adding 4 to the subsequent terms:

The sequence will be:

12,16,20,24,28,32,36,...

Therefore the seventh term is 36.

2) The sequence is recursively defined by;

a_1=20\\  a_n=a_{n-1} - 5

This means, we have to keep subtracting 5 from the subsequent terms.

The sequence will be;

20,15,10,5,...

Therefore the fourth term is 5

3) The sequence is recursively defined by:

f(n+1)=f(n)+0.5

where f(1)=-1.5

This means that, the subsequent terms can be found by adding 0.5 to the previous terms.

The sequence will be:

-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....

Therefore f(10)=3.0

8 0
4 years ago
On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What
KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: \mu=np

Therefore, \mu=10(0.05)=0.5

Variance of binomial random variable: \sigma^2=npq

Therefore, \sigma^2=10(0.05)(0.95)=0.475

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0
3 years ago
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