Answer:
#include <iostream>
using namespace std;
void OutputValues(int n1, int n2) {
for (int i = n1; i <= n2; i++) {
cout << i << endl;
}
}
int main() {
int num1;
int num2;
cin >> num1 >> num2;
OutputValues(num1, num2);
return 0;
}
Explanation:
Answer:
umm... I hate to break it to you but this is something you're gonna have to do on your own since the likelihood of someone being in your exact class is very low I mean people could write some random stuff in here but if it doesn't match up with what you learned in class then does it really even matter at that point? your teacher will know you cheated and will probably make you do it from scratch and will check thoroughly to make sure it's your work (if you're in highschool and/or the teacher is nice enough to give you a second chance) or just fail you completely (if you're in college and/or just have a really mean teacher who doesn't give second chances). so I recommend taking the time to do this yourself and not risking the consequences.
Explanation:
Answer:
Explanation:
Try as much as possible, to keep like files together in one folder. Even so there if you run into the hundreds or thousands, that is not going to be an easy thing do.
What ever you do, do clutter up your favorites bar, especially if your favorites spill over into where you have to push a button to get to them. Keep that bar open for what you really need on that bar. Mine has Brainly, Kitco, My Alberta Health, A graphing program, a second graphing program, Amazon, a scrabble word finder, and a couple of other things. It
If you can, try and keep your favorites to something that would be useless to anyone else. My favorites are worthless to anyone else. But I play a lot of scrabble related games.
Moderno = mordern, if It does than yes!
Answer:
True.
Explanation:
When determining the order of magnitude of an algorithm using the Big-Oh algorithm analysis.The instruction which evaluates to O(c) is equal to one that is O(1) because it is considered as constant time and to represent constant we use O(1) in big-Oh notation.
Hence the answer to this question is True.
