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kvasek [131]
3 years ago
8

Give an example of a situation in which a compromise of Confidentiality leads to compromise in Integrity.Situation where confide

ntiality leaks lead to compromised integrity would the the compromise of a password or cryptic key that is ultimately protecting the integrity of the system.
Computers and Technology
1 answer:
il63 [147K]3 years ago
7 0

Answer: An example of such a scenario would be when the user name and password meant to allow access to a customers bank account statement is cracked by unauthorized people this causing alteration (in the form of data diddling attacks) in the data contained in the statement. This is a compromise in integrity.

Explanation:

Confidentiality entails securing things people want to remain secret. An account statement of a bank customer is a confidential document which is to be kept secret. A password allows access to it.

Integrity implies receiving a sent data/information as accurately as it came from a sender. A data diddling attack alter integrity because the original information is altered by an unauthorized person.

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Network Architecture and Topology: Mastery Test
trasher [3.6K]

Answer:

You need to understand all the network typologies and the devices that we use in the Computer networks. You also use the techniques like routing, masking, firewalls, VPN, as well as the network protocol. And recently added is the PKI. And hence you need to make sure that you know all these, and you should also know ipv4 and ipv6. Rest you can consult Tanenbaum for further studies on Computer Network.

Explanation:

Please check the answer.

4 0
3 years ago
Create a function that will perform linear interpolation from a set of measured data stored in a list or array. The function sho
wel

Answer:

This question is incomplete, here is the complete question:

Python

a) You should create a function that will perform linear interpolation from a set of measured data. The function should take as input a list of values at which samples were taken, and then another list giving the measurements (you can assume each measurement is a single value) at those values. It should also take in a query value, and should give the best estimate it can of the value at that query. Be sure to handle values that are outside of the range, by extrapolating. You should write a program that allows you to test your function by reading the lists from a file where each line of the file is a pair of numbers separated by spaces: the value where the sample was taken, and the measurement at that value. Your program should ask the user for the name of the file and for a query value. Important: The two lists will correspond to each other: i.e. for the i-th value in the first list, the measurement will be the i-th element of the second list (these are called parallel lists or arrays). But, you should not assume that the input values are in increasing/decreasing order. That is, the values in the first list can be in any random ordering, not necessarily from smallest to largest or largest to smallest. You will have to account for this in your program, and there is more than one way to do so. You should discuss what options you can think of to handle the data arriving in any order like that, and decide what you think the best option for handling it is.

Explanation:

from __future__ import division

from cStringIO import StringIO

import numpy as np

from scipy.interpolate import RectBivariateSpline

np.set_printoptions( 1, threshold=100, edgeitems=10, suppress=True )

   # a file inline, for testing --

myfile = StringIO( """

# T P1 P2 P3 P4

0,   80,100,150,200

75, 400,405,415,430

100, 450,456,467,483

150, 500,507,519,536

200, 550,558,571,589

""" )

   # file -> numpy array --

   # (all rows must have the same number of columns)

TPU = np.loadtxt( myfile, delimiter="," )

P = TPU[0,1:] # top row

T = TPU[ 1:,0] # left col

U = TPU[1:,1:] # 4 x 4, 400 .. 589

print "T:", T

print "P:", P

print "U:", U

interpolator = RectBivariateSpline( T, P, U, kx=1, ky=1 ) # 1 bilinear, 3 spline

   # try some t, p --

for t, p in (

   (75, 80),

   (75, 200),

   (87.5, 90),

   (200, 80),

   (200, 90),

   ):

   u = interpolator( t, p )

   print "t %5.1f p %5.1f -> u %5.1f" % (t, p, u)

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<span>An ftp server is a computer that allows users to upload and/or download files using ftp.</span>
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Answer:

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