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alexgriva [62]
4 years ago
7

What's the product of 42⁄3 and 111⁄4 ?

Mathematics
2 answers:
olga nikolaevna [1]4 years ago
4 0

4 2/3 * 11   1 /4

change to improper fractions

 4  2/3 =(3* 4+2)/3  = 14/3  

11 1/4 = (4* 11+1)/ 4 =45/4

14/3 * 45/4 = 630/12

105/2

52 1/2


Ksenya-84 [330]4 years ago
4 0

Answer:

Option A - 4\frac{2}{3}\times11\frac{1}{4}=52\frac{1}{2}        

Step-by-step explanation:

Given : Numbers 4\frac{2}{3} and 11\frac{1}{4}

To find : What's the product of number ?

Solution :  

Step 1 - Write the number in product form,

4\frac{2}{3}\times11\frac{1}{4}

Step 2 - Write the mixed fraction into simpler fraction,

4\frac{2}{3}\times11\frac{1}{4}=\frac{14}{3}\times \frac{45}{4}

Step 3 - Multiply the numerator by numerator and denominator by denominator,

4\frac{2}{3}\times11\frac{1}{4}=\frac{630}{12}

Step 4 - Write in simpler form,,

4\frac{2}{3}\times11\frac{1}{4}=\frac{105}{2}

Step 5 - Write in mixed fraction,

4\frac{2}{3}\times11\frac{1}{4}=52\frac{1}{2}

Therefore,Option A is correct.

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A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line. He must recalibrate his machines
storchak [24]

Answer:

The null hypothesis is H_o: \mu = 4.

The alternate hypothesis is H_a: \mu \neq 4

The pvalue of the test is 0.0182 < 0.05, which means that there is sufficient evidence to show that the manufacturer needs to recalibrate the machines.

Step-by-step explanation:

A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line.

This means that the null hypothesis is that they are 4.00 cm long, that is:

H_o: \mu = 4

At the alternate hypothesis we test if it is different. So

H_a: \mu \neq 4

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4 is tested at the null hypothesis:

This means that \mu = 4

After sampling 196 randomly selected bolts off the assembly line, he calculates the sample mean to be 4.14 cm.

This means that n = 196, X = 4.14

He knows that the population standard deviation is 0.83 cm.

This means that \sigma = 0.83

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{4.14 - 4}{\frac{0.83}{\sqrt{196}}}

z = 2.36

Pvalue of the test and decision:

The pvalue of the test is the probability that the sample mean is different by at least 4.14 - 4 = 0.14 from the target value, which is P(|z| > 2.36), which is 2 multiplied by the pvalue of z = -2.36.

Looking at the z-table, z = -2.36 has a pvalue of 0.0091

2*0.0091 = 0.0182

The pvalue of the test is 0.0182 < 0.05, which means that there is sufficient evidence to show that the manufacturer needs to recalibrate the machines.

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Answer:

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  • Scott: 19
  • Laura: 28

Step-by-step explanation:

Let s represent the number of orders Scott served. Then we have Joe served 3s, and Laura served (s+9). The total of orders served is ...

  3s +s +(s +9) = 104

  5s = 95 . . . . . . . . . . . subtract 9 and collect terms

  s = 19 . . . . . . . . . divide by 5

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Joe served 57 orders, Scott served 19, and Laura served 28 orders.

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6:00 PM equals 18:00 in 24 hrs clock time.

<h3>Hope it helps you.. </h3>

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