Answer: y = -3(x + 
)² + 
, 
, 
<u>Step-by-step explanation:</u>
First, you need to complete the square:
y = -3x² - 5x + 1
<u> -1 </u> <u> -1 </u>
y - 1 = -3x² - 5x
y - 1 = -3(x² + 
y - 1 + -3(
) = -3(x² + + )
↑ ↓ ↑
= 
y - 1 - 
= -3(x + )²
y - 
- = -3(x + )²
y - = -3(x + )²
y = -3(x + )² +
Now, it is in the form of y = a(x - h)² + k <em>where (h, k) is the vertex</em>
Vertex = ,
Answer:
KL = 5.25
LJ = 6
Step-by-step explanation:
i don’t know the first one
Answer:
x=g-c
Step-by-step explanation:
Answer:
The zeros are:
- The function has three distinct real zeros.
Hence, option (B) is true.
Step-by-step explanation:
Given the expression
Let us determine the zeros of the function by putting h(x) = 0 and solving the expression
switch sides
as
so
Using the zero factor principle
so
Thus, the zeros are:
It is clear that there are three zeros and all the zeros are distinct real numbers.
Therefore,
- The function has three distinct real zeros.
Hence, option (B) is true.
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
