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3 years ago

To find the interquartile range you need to ____the upper and lower quartile values.

Mathematics

2 answers:

Blababa [14]3 years ago

8 0

Answer:

The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

EleoNora [17]3 years ago

5 0

Answer:

Calculate the median of

Step-by-step explanation:

Found on G O O G L E. Sorry if it's wrong.

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Help please <br> 1 3/5 x 2 1/3=

Crank

Answer:

= 56/ 15 and 3 11/15

Step-by-step explanation:

1 3/5 x 2 1/3

= 8/5 x 7/3

3 0

3 years ago

Find the radius of convergence of the power series. (if you need to use or –, enter infinity or –infinity, respectively. ) [infi

Alona [7]

For given power series $\sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}$ the radius of convergence is 2.

For given question,

We have been given a power series $\sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}$

We need to find the radius of convergence of the power series.

We use ratio test to find the radius of convergence of the power series.

Let $a_n=\frac{(-1)^nx^n}{2^n}$

$\Rightarrow a_{n+1}=\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}$

Consider,

$\lim_{n \to \infty}|\frac{a_{n+1}}{a_n} |\\\\= \lim_{n \to \infty} |\frac{\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}}{ \frac{(-1)^nx^n}{2^n} } |\\\\=\lim_{n \to \infty} |\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}\times \frac{2^n}{(-1)^nx^n} |\\\\=\lim_{n \to \infty} |\frac{(-1)x}{2} |\\\\=\lim_{n \to \infty}|\frac{-x}{2} |\\\\=\frac{x}{2}$

By Ratio test, given power series converges at $|\frac{x}{2} | < 1$

⇒ |x| < 2

So, the radius of convergence is 2.

Therefore, for given power series $\sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}$ the radius of convergence is 2.

Learn more about the radius of convergence here:

brainly.com/question/2289050

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8 0

2 years ago

24 points scored in 4 games; α points scored in 10 games

Svetllana [295]

Answer:

a=60

Step-by-step explanation:

3 0

3 years ago

the population of masterton was 23 000 in 2012. Assume that Masterton population increases at a rate of 2% per year. Write an eq

Oksanka [162]

So, let's first focus on the first year:

the population then would be: 23000* (100+2)%

100% is the old population the 2% is the incease, so in total it's 102%, or 1.02 - the same number written differently.

So it will be 23000*1.02

After two years it will be 23000*1.02*1.02, and so on

so after x years it will be:

y=23000* $1.02^{z}$

8 0

4 years ago

Solve for x<br> (x+54)<br> 5x

valina [46]

X=9

You would do 54 divided by 5x and it would equal to 9 that means x is 9

4 0

3 years ago

Read 2 more answers

To find the interquartile range you need to ____the upper and lower quartile values.​

To find the interquartile range you need to ____the upper and lower quartile values.