Question

What is the value of x in this figure?

Answer 1

Here we use the Pythagoras theorem

According to this, in a right angled triangle, the sum of the squares of the lengths of the two sides is equal to the hypotenuse

is "a" and "b" are the sides, and "h" is the hypotenuse, then :

$a^{2}+ b^{2} = h^{2}$

In the given problem, a = b = 12 and h = x

12^2 + 12^2 = x^2

So, x =$\sqrt{12^{2} + 12^2$

x = $\sqrt{144 + 144}$

X =$\sqrt{288}$

X = 12$\sqrt{2}$ (Option B)

Answer 2

The answer is the second choice, 12√2