The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.
An exterior angle of a triangle is equal to the sum of the two opposite interior angles. Example : Find the values of x and y in the following triangle. y + 92° = 180° (interior angle + adjacent exterior angle = 180°.)
Ausrdi scrambled is radius
Product is multiplication.
The first part would be x(6+8) , x times the sum of 6 plus 8.
The second part would be written as x^2, the square of x
Now combine to get:
x(6+8) * x^2
The third one is the answer
