All categories

3 years ago

Alright need answers for number 25-28 on This packet please reply To My question I posted

Mathematics

1 answer:

den301095 [7]3 years ago

5 0

Q25 is D, Q26 is A, & Q28 is 6. Sorry, I'm not sure how to calculate Q27

You might be interested in

im rlly confused (its yes and no answers)Decide if each pair of expressions is equivalent.6(-4t + 5) and -2(15 - 12t)1/5(20t - 1

kirill [66]

Given data:

The expression of the first option is,

$\begin{gathered} \text{6(-4t+5})and\text{-2(15}-12t) \\ =-6(5-4t) \end{gathered}$

Thus, the above expression are not equivalent.

The expression in the second option is,

$\begin{gathered} \frac{1}{5}(20t-15)\text{ and }4t-3 \\ 4t-3\text{ and 4t-3} \end{gathered}$

Thus, yes they are equivalent.

The expression in the third option is,

$\begin{gathered} 1.5\text{ }-2\text{t and 0}.25(8-6t) \\ 1.5\text{ }-2\text{t and 2-1.5t} \end{gathered}$

Thus, the above expression are not equivalent.

The expression in fourth option is,

$\begin{gathered} -3(t-7+5t+8)\text{ and }-18t-3 \\ -3(6t+1)\text{ and -18t-3} \\ -18t-3\text{ and -18t-3} \end{gathered}$

Thus, yes the above expression is equivalent.

3 0

2 years ago

HELP ME ASAP PLEASE will give brainliest

Talja [164]

Step-by-step explanation:

A) opposite sides in a rectangle is always equal

B) 9x+12 = 4x +47

Transpose = 9x - 4x = 47 - 12

solve = 5x = 35

Divide both sides by 5

x = 7

5 0

3 years ago

Read 2 more answers

Simplify x^4y^3 over x^2y^5

jek_recluse [69]

$\dfrac{x^4y^3}{x^2y^5} =$

$= \dfrac{x^2}{y^2}$

4 0

3 years ago

Read 2 more answers

-565/5=? Show how you got the answer

bixtya [17]

Answer:

-113 is the right answer. You can use the attachment above ^w

4 0

3 years ago

How to display the work for this problem. -2x-3=8 -2x+4y=22 Answer (-7,2)

Nezavi [6.7K]

Assuming that this particular type of question is a system of equations one. More specifically linear equations, you would simply substitute one of the equations into the other one. Then upon doing so, plug in the x and y coordinates for the point into the x and y variables of the equation and then see if it is a solution, by checking if the left hand side of the equation equals that of the right hand side of the equation.

7 0

4 years ago