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3 years ago

Simplify x^4y^3 over x^2y^5

Mathematics

2 answers:

jek_recluse [69]3 years ago

4 0

$\dfrac{x^4y^3}{x^2y^5} =$

$= \dfrac{x^2}{y^2}$

kondaur [170]3 years ago

4 0

If you mean (x^4 * y^3) over (x^2 * y^5) it simplifies to

x^2/y^2

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I’m sorry I ain’t good at this math please help

otez555 [7]

The answer would be 2160 because v=l*w*h so 10*12*18 would equal 2160

4 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

Please help me!

Reil [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2/9 of the members are boys in a community service club. if there are 95 more girls than boys, how many girls are there in club?

Talja [164]

Answer:

There are 171 members in the club

Number of boys = 38

Number of girls = 133

Step-by-step explanation:

Let

x = total members of the club

Boys = 2/9x

if there are 95 more girls than boys

Girls = 2/9x + 95

how many girls are there in club?

Total members in the club = boys + girls

x = 2/9x + 2/9x + 95

x = 2+2/9x + 95

x = 4/9x + 95

x - 4/9x = 95

9x-4x/9 = 95

5/9x = 95

Divide both sides by 5/9

x = 95 ÷ 5/9

= 95 × 9/5

= 855/5

= 171

boys = 2/9x

= 2/9 * 171

= 342 / 9

= 38

Girls = 2/9x + 95

= 38 + 95

= 133

Total = 38 + 133

= 171

There are 171 members in the club

Number of boys = 38

Number of girls = 133

5 0

3 years ago

A certain star is 2.6×102 light years from the Earth. One light year is about 5.9×1012 miles. How far from the earth (in miles)

navik [9.2K]

Answer:

2.5 x $10^{15}$ miles

3 0

2 years ago

Read 2 more answers