2 years ago

Simplify x^4y^3 over x^2y^5

Mathematics

2 answers:

jek_recluse [69]2 years ago

4 0

$\dfrac{x^4y^3}{x^2y^5} =$

$= \dfrac{x^2}{y^2}$

kondaur [170]2 years ago

4 0

If you mean (x^4 * y^3) over (x^2 * y^5) it simplifies to

x^2/y^2

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Lol can you help if you can

ratelena [41]

Answer:

y= (x - 12)^3

y= (x - 4)^3

Step-by-step explanation:

Shift to the right is a horizontal shift so it needs to be with x in the parenthesis. And negative because it is to the right.

y= (x - 12)^3

y= (x - 4)^3

are the two that fit those criteria

3 0

2 years ago

Read 2 more answers

What is the maximum number of possible solutions for the system shown below?

julsineya [31]

$\bf \begin{cases} 3x^2+y^2=4\\[-0.5em] \hrulefill\\ x^2+y=5\implies \boxed{y}=5-x^2 \end{cases} \\\\\\ \stackrel{\textit{substituting \boxed{y} in the 1st equation}}{3x^2+\left( \boxed{5-x^2} \right)^2=4}\implies 3x^2+25-10x^2+x^4=4 \\\\\\ x^4-8x^2+21=0\impliedby \begin{array}{llll} \textit{the degree of this polynomial}\\ \textit{is 4, and by the fundamental}\\ \textit{theorem of algebra, it can}\\ \textit{have \boxed{4} solutions at most} \end{array}$