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Arada [10]
4 years ago
13

Write the equation 2x 2 - 4x + 6 = 1 in standard form and then choose the value of "c."

Mathematics
2 answers:
NARA [144]4 years ago
5 0
Subtract -1 on both sides to get equation into standard form
2x^2 - 4x + 5.
The C value would be 5
andreyandreev [35.5K]4 years ago
4 0

Answer:

c = 5

Step-by-step explanation:

 Given equation 2x^2 - 4x + 6 = 1

We have to Write the equation 2x^2 - 4x + 6 = 1 in standard form and then choose the value of "c."

The standard form of the quadratic equation is given as ax^2=bx+c=0, where a , b and c are the coefficients.

Consider the given equation 2x^2 - 4x + 6 = 1

Subtract 1 both sides, we have,

2x^2 - 4x + 6-1=1-1

simplify, we have,

2x^2 - 4x + 5=0

Now on comparing with standard form we get,

a = 2 , b = -4 and c = 5

Thus ,  c = 5

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3 years ago
Which is equivalent to the following expression (3m^2+2mn-n^2)+(m^2+4mn-n^2)
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Answer:

<h3>4m² + 6mn - 2n²</h3>

Step-by-step explanation:

(3m^2+2mn-n^2)+(m^2+4mn-n^2)\\\\=3m^2+2mn-n^2+m^2+4mn-n^2\qquad\text{combine like terms}\\\\=(3m^2+m^2)+(2mn+4mn)+(-n^2-n^2)\\\\=\boxed{4m^2+6mn-2n^2}

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Two hikers are 22 miles apart and walking toward each other. They meet in 5 hours. Find the rate of each hiker if one hiker walk
Irina-Kira [14]

Answer:

The hikers A and B travel at rates of 1.1 miles per hour and 3.3 miles per hour, respectively.

Step-by-step explanation:

Let suppose that each hiker travels at constant speed, such that kinematic formulas are, respectively:

Hiker A

x_{A} = x_{A,o}+v_{A}\cdot t

Hiker B

x_{B} = x_{B,o} +v_{B}\cdot t

Relationship

v_{A} =- v_{B}-2.2\,mph (They walk toward each other)

Where:

x_{A,o}, x_{A} - Initial and final position of the hiker A, measured in miles.

x_{B,o}, x_{B} - Initial and final position of the hiker B, measured in miles.

t - Time, measured in hours.

v_{A}, v_{B} - Velocities of hikers A and B, measured in miles per hour.

Given that x_{A,o} = 0\,mi, x_{B,o} = 22\,mi, x_{A} = x_{B} and t = 5\,h, the system of equation is reduced to the following:

0\,mi -(v_{B}+2.2\,mph)\cdot (5\,h) = 22\,mi+v_{B}\cdot (5\,h)

-5\cdot v_{B}-11 = 22+5\cdot v_{B}

10\cdot v_{B} = -33

v_{B} = -3.3\,mph

Now, the velocity of the hiker A is:

v_{A} = - (-3.3\,mph)-2.2\,mph

v_{A} = 1.1\,mph

The hikers A and B travel at rates of 1.1 miles per hour and 3.3 miles per hour, respectively.

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3 years ago
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