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AlekseyPX
3 years ago
7

The _______ helps to resist changes in pH.

Biology
2 answers:
olga_2 [115]3 years ago
7 0
It is the blood helps to resist change ph
SVEN [57.7K]3 years ago
7 0

Answer:

blood

Explanation:

i took the quiz

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What are the stages of secondary succession
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Sequence of events that occur in secondary succession

Secondary succession is one of the two types ecological succession of a plants life. As opposed to the first, primary succession, secondary succession is a process started by an event (e.g. forest fire, harvesting, hurricane, etc.) ... Seeds, roots and underground vegetative organs of plants may still survive in the soil

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Which is an application of DNA technology in medicine?
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determining hereditary diseases in individuals and families

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A population of Muscovy ducks contains 13 birds with black masks and 37 birds with red masks. Red masks are the dominant trait.
Semmy [17]

Answer: Black allele has frequency of 0.14.

              Red allele has frequency of 0.86.

             The frequency of heterozygotes is 0.241

Explanation: <em>Hardy-Weinberg model </em>states the frequency of alleles in a population will stay in equilibrium as long as there are external influences. It is also used to determine alleles frequencies using the following equations:

p+q=1

p^{2}+2pq+q^{2}=1

p represents frequency of dominant allele;

q represents frequency of recessive allele;

2pq is frequency of heterozygotes;

For the frequency of red allele, which is dominant, we can use:

p^{2}=\frac{37}{13+37}

p^{2}=\frac{37}{50}

p^{2}=0.74

p=\sqrt{0.74}

p = 0.86

For the black allele:

p+q=1

q=1-p

q=1-0.86

q = 0.14

Frequency of heterozygotes is

2pq = 2(0.86)(0.14)

2pq = 0.241

<u>Frequencies for a population of Muscovy ducks are </u><u>0.86 for red allele, 0.14 for black allele and 0.241 for heterozygote.</u>

5 0
3 years ago
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