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4 years ago

Where do y=10x+20 and y=5x+50 intercept

Mathematics

1 answer:

Sholpan [36]4 years ago

4 0

Point of intersection is: (6,80)

Step-by-step explanation:

In order to find the point of intersection for two lines we solve the equations.

Given equations are:

$y = 10x+20\ \ \ Eqn1\\y = 5x+50\ \ \ Eqn2$

Putting y = 5x+50 in equation 1

$5x+50 = 10x+20\\50-20 = 10x-5x\\5x = 30\\\frac{5x}{5} = \frac{30}{5}\\x = 6$

Putting x=6 in equation 1

$y = 10(6)+20\\y = 60+20\\y = 80$

Hence,

Point of intersection is: (6,80)

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

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An earthquake was felt throughout a circular area of 1,808.64 square miles. What was the radius of the circular area?

spin [16.1K]

A. 24 miles

Explanation:

the area inside a circle is given by:

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In this problem, we know the circular area:

$A=1,808.64 mi^2$

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3 years ago

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3 years ago

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3 years ago

Which statement best describes the triangle formed by joining the points A(-3,6),B(-11,2),C(-4,-2)

Vikki [24]

Answer:

Isosceles triangle

Step-by-step explanation:

Length of side AB = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(-11+3)^2+(2-6)^2}$

= $\sqrt{64+16}$

= $\sqrt{80}$

= 4 $\sqrt{5}$

Length of BC = $\sqrt{(-4+11)^2+(-2-2)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

Length of AC = $\sqrt{(-3+4)^2+(6+2)^2}$

= $\sqrt{1+64}$

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3 years ago

X/5 = -2 solve for x<br><br> plz help me ASAP

irina [24]

Hi!

We will solve this by simply multiplying both sides of the equation with 5, like this:

$\frac{x}{5} = -2 / *5 \\ x = -10$

Hope this helps!

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3 years ago