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nevsk [136]
3 years ago
12

Where do y=10x+20 and y=5x+50 intercept

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Point of intersection is: (6,80)

Step-by-step explanation:

In order to find the point of intersection for two lines we solve the equations.

Given equations are:

y = 10x+20\ \ \ Eqn1\\y = 5x+50\ \ \ Eqn2

Putting y = 5x+50 in equation 1

5x+50 = 10x+20\\50-20 = 10x-5x\\5x = 30\\\frac{5x}{5} = \frac{30}{5}\\x = 6

Putting x=6 in equation 1

y = 10(6)+20\\y = 60+20\\y = 80

Hence,

Point of intersection is: (6,80)

Keywords: Linear equations, variables

Learn more about linear equations at:

  • brainly.com/question/5639299
  • brainly.com/question/563623

#LearnwithBrainly

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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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Solve for W. What does W equal?
Nostrana [21]

Answer:

w=-11/6

Step-by-step explanation:

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I would say about 6.25 hours
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Answer:

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Step-by-step explanation:

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Plz tell me the aswer and how you worked it out. A tree grows to a height of 13.75m over 5 1/2 years. What is the average annual
marin [14]
1. Take your 13.75 and 5 1/2 and put it into a dividing table 
           _______
     5.5 I13.75               

                              you need to get your decimal out of deviser (5.5) will now be (55) because you moved the decimal over there you also need to move the decimal that is on the inside to and it will be (137.5)

2. When you divide you would get 2.5 

3. Now you would know how much the tree grew over the 5 1/2 years.

ANSWER:  2.5m a year!

Hope this helped! 

:)
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