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xeze [42]
3 years ago
6

Plz tell me the aswer and how you worked it out. A tree grows to a height of 13.75m over 5 1/2 years. What is the average annual

growth rate in metres per year?
Mathematics
1 answer:
marin [14]3 years ago
4 0
1. Take your 13.75 and 5 1/2 and put it into a dividing table 
           _______
     5.5 I13.75               

                              you need to get your decimal out of deviser (5.5) will now be (55) because you moved the decimal over there you also need to move the decimal that is on the inside to and it will be (137.5)

2. When you divide you would get 2.5 

3. Now you would know how much the tree grew over the 5 1/2 years.

ANSWER:  2.5m a year!

Hope this helped! 

:)
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Please answer this question
Gnesinka [82]

Answer:

There are 20 kids total in the class.

Step-by-step explanation:

15/100 × 20 = 3  

You can use direct proportion for any percent calculation.

Compare each number with its percent.

3 i s  15 %  of what number? Let the number be  x

So, 3  represents  15 %  and  x  represents  100 %

x/ 100   =  3/15  

Multiply by  100  to isolate  x

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3 0
3 years ago
HELPPP ASAPPP DUE SOONN
Andru [333]

The friction force exerted on the 2400kg car is 9408 Newtons

<h3>What force will be exerted on the 2400kg car?</h3>

First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:

F = k*M

Where F is the force, M is the mass and k is the constant of proportionality.

We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:

6272N = k*1600kg

Solving for k we get:

k  = (6272N)/(1600 kg) = 3.92 N/kg

Then the proportional relationship is:

F = (3.92 N/kg)*M

So if M = 2400kg, we have:

F = (3.92 N/kg)*2400kg = 9408 N

So the friction force exerted on the 2400kg car is 9408 Newtons

If you want to learn more about proportional realtions:

brainly.com/question/12242745

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8 0
2 years ago
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