V=<span>πr^2h
V=</span><span>π(5^2)(9)
V=</span><span>π(25)(9)
V=225</span><span>π
i hope this helps!</span>
Answer:
28.57% probability that the oldest is a girl and the youngest is a boy, given that there is at least one boy and at least one girl.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
These are all the possible outcomes: from youngest to oldest, b is boy and g is girl
b - b - b - g
b - b - g - b
b - b - g - g
b - g - b - b
b - g - b - g
b - g - g - b
b - g - g - g
g - b - b - b
g - b - b - g
g - b - g - b
g - b - g - g
g - g - b - b
g - g - b - g
g - g - g - b
The nuber of total outcomes is 14.
Desired outcomes:
Oldest(last) girl, youngest(first) boy
b - b - b - g
b - b - g - g
b - g - b - g
b - g - g - g
So 4 desired outcomes
Probability:
4/14 = 0.2857
28.57% probability that the oldest is a girl and the youngest is a boy, given that there is at least one boy and at least one girl.
A•b = 7*4 +(-4)*3
= 28 -12
= 16 . . . . . matches selection B
3 hours : 1 day
Just do it as though it were a fraction
Answer:
9 tickets
Step-by-step explanation:
Let x = the number of tickets
let y = the total she spends
So y = 5 + 8 + 0.75x
If the max she can spend is 20, set y = 20 and solve for x:
5 + 8 + 0.75x = 20
13 + 0.75x = 20
0.75x = 20 - 13
0.75x = 7
x = 7 ÷ 0.75 = 9.333333333
Therefore, the max number of tickets that can be bough is 9