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Vera_Pavlovna [14]
3 years ago
5

Identify the middle line for the function.

Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0
The solution to the problem is as follows:

<span>'(t) = 0 gives:
 
-24t + 60 = 0
 
t = 2.5
 
For this t, the second derivative s"(t) = -24 is negative.

And so, s(t) is maximum for t = 2.5.
 
Maximum height is:
 
S = -12(2.5)^2 + 60(2.5) +8 = 233ft
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
soldi70 [24.7K]3 years ago
6 0
Hello there.

<span>Identify the middle line for the function.

Identify the middle line for the function: f (t) = 5sec(3t − π) + 1.

</span><span>y = 2
</span>
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Tn = a + ( n - 1) d

T62 = - 21 + ( 62 - 1 ) - 6

= - 21 -366

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For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
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