3 years ago

Continuity M8 Orade & PreAlgebra Qun 4 (8V10-20) UPDATED

Mathematics

1 answer:

VashaNatasha [74]3 years ago

6 0

Answer:

attendance at 2year and 4year colleges

a= 69.1%

b= 30.9%

c=68.6%

d=31.4%

for statistics

Step-by-step explanation:

edge

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Cual es la de Raiz de 2000

serg [7]

2000 | 2

1000 | 2

500 | 2

250 | 2

125 | 5

25 | 5

5 | 5

√2000 = √2².√2².√5².√5

√2000 = 2.2.5√5

√2000 = 20√5

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3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

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2 years ago

Help help help pls help

Brilliant_brown [7]

AB = 6.1

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