Answer:
A clock is started at noon. By 10 minutes past 5, the hour hand has turned through: ... Angle traced by hour hand in 12 hrs = 360°.Jul 1, 2010
Answer:
1. x=27
2. x=3
Step-by-step explanation:
<h3>the first one </h3>
let's solve your equation step-by-step.
x−7=20
Step 1: Add 7 to both sides.
x−7+7=20+7
<h3>the second one </h3>
Let's solve your equation step-by-step.
3x+6=12x−21
Step 1: Subtract 12x from both sides.
3x+6−12x=12x−21−12x
−9x+6=−21
Step 2: Subtract 6 from both sides.
−9x+6−6=−21−6
−9x=−27
Step 3: Divide both sides by -9.
−9x/−9=−27/−9
<h3 />
Answer:
8 = 4 +$
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
6a^2 is the formula
plug in and solve
Answer:
a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.
(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.
Step-by-step explanation:
Given:
n_1 = 20
x_1= 40
s_1 = 3
n_2 = 20
x_2= 43
s_2 = 2
d_f = 33.1
c = 95%. 0.95
(a) Determine the t-value by looking in the row starting with degrees of freedom df = 33.1 > 32 and in the column with c = 95% in the Student's t distribution table in the appendix:
t
/2 = 2.037
The margin of error is then:
E = t
/2 *√s_1^2/n_1+s_2^2/n_2
E = 2.037 *√3^2/20+s_2^2/20
= 1.64
The endpoints of the confidence interval for u_1 — u_2 are:
(x_1 — x_2) — E = (40 — 43) — 1.6423 = —3 — 1.6423= —4.6423
(x_1 - x_2) + E = (40 — 43) + 1.6423 = —3 + 1.6423= —1.3577
a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.
(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.