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Annette [7]
2 years ago
6

1.x-7=202.3x+6=12x-21​

Mathematics
1 answer:
dusya [7]2 years ago
8 0

Answer:

1. x=27

2. x=3

Step-by-step explanation:

<h3>the first one </h3>

let's solve your equation step-by-step.

x−7=20

Step 1: Add 7 to both sides.

x−7+7=20+7

<h3>the second one </h3>

Let's solve your equation step-by-step.

3x+6=12x−21

Step 1: Subtract 12x from both sides.

3x+6−12x=12x−21−12x

−9x+6=−21

Step 2: Subtract 6 from both sides.

−9x+6−6=−21−6

−9x=−27

Step 3: Divide both sides by -9.

−9x/−9=−27/−9

<h3 />
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Given f(x) and g(x) = f(x + k), use the graph to determine the value of k.
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g(x) is basically transformed f(x). First, let's focus on f(x) graph. Notice how the graph has slope of 1 and intersect y-axis at (0,0).

Which means that our equation for f(x) is:

\large{f(x) = x}

Now then we focus on g(x). g(x) is f(x+k). That means if f(x) = x then f(x+k) would mean substitute x = x+k in the equation.

\large{f(x + k) = x + k }\\  \large{g(x) = x + k}

Next, we want to find the value of k. In the slope-intercept form or y = mx+b where m = slope and b = y-intercept. Notice the g(x) graph and see that the graph intersects y-axis at (0,4). Therefore k = y-intercept = 4.

\large{g(x) = x + 4}

Answer

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Graph ARST with vertices R(6, 6), S(3, -6), and T(0, 3) and its image after a
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Answer:

The answer is the second figure and the vertices of Δ R'S'T' are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) reflected across the x-axis

 ∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

 ∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

 ∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

 ∴ Its image is (-y , -x)

- Now we can solve the problem

∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST

- The triangle RST is reflected over the y-axis

- According to the rule above the signs of x-coordinates will change

∵ R = (6 , 6)

∴ Its image is (-6 , 6)

∵ S = (3 , -6)

∴ Its image is (-3 , -6)

∵ T = (0 , 3)

∴ Its image is (0 , 3)

* Now lets look to the figure to find the correct answers

- The image of Δ RST is ΔR'S'T'

∵ The vertices of the image of ΔRST are:

  R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

* The answer is the second figure

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