the height of the house is 
.
<u>Step-by-step explanation:</u>
Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find What is the height of the house . Let's find out:
Let y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.
Distance of house from point A( initial point ) = x ft
Distance of house from point B( when she traveled 200 ft towards street = x-200 ft
Now , According to question these scenarios are of right angle triangle as
At point A
⇒ 
⇒ 
⇒ 
..................(1)
Also , At point B
⇒ 
⇒ 
..............(2)
Equating both equations:
⇒ 
⇒ 
⇒ 
⇒ 
Putting in we get:
⇒
⇒ 
⇒ 
Therefore , the height of the house is .
Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.
Step-by-step explanation:
I suppose that the "legs" of a triangle rectangle are the cathati.
if L is the length of the shorter leg, 2*L is the length of the longest leg.
Now you can remember the relation:
Tan(a) = (opposite cathetus)/(adjacent cathetus)
Then there is one acute angle calculated as:
Tan(θ) = (shorter leg)/(longer leg)
Tan(φ) = (longer leg)/(shorter leg)
And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.
Then we need to find θ and φ.
Tan(θ) = L/(2*L)
Tan(θ) = 1/2
θ = Atan(1/2) = 26.57°
Tan(φ) = (2*L)/L
Tan(φ) = 2
φ = Atan(2) = 63.43°
Then the ratio between the larger acute angle and the smaller acute angle is:
R = (63.43°)/(26.57°) = 2.39
This means that the larger acute angle is 2.39 times the smaller acute angle.
Answer:
3x(x-1)-5(x-1)
=3x²-3x-5x+5 (we can count it one by one)
=3x²-8x+5 (we can calculate the same variable)
#i'm from indonesia
hope it helps.
The answer is 0,4,known ás the answer C
