Answer:
radius= 4.5
Step-by-step explanation:
to find the radius of a circle given circumference you have to use the formula:
r=C/2π
divide: 28.27 / 2π
this equals
4.5
your welcome!
Answer:
x=6/5 or 1.2
Step-by-step explanation:
I could not tell if your original problem was 2=-5x+8 or if it should have been 2x=-5x+8 so I solved both
2= -5x+8 (next subtract 8 from both sides)
-6= -5x (divide both sides by -5)
-6/-5=x (the negative cancel out next)
6/5 or 1.20 is x
If your original problem should say 2x=-5x+8
2x=-5x+8 (add 5x to both sides next)
7x=8 (divide by 7 on both sides)
x=8/7
Each cup is 8 fl oz,and there are 16 cups in a gallon, so you would do 16 times 8 and get 128. And then you would multiply that by two because there are two gallons and so the answer would be 256 fl oz.
Refer to the attached diagram for further a visual explanation. As per the given information, segments (AB) and (AD) are congruent. Moreover, segments (AC) and (AE) are also congreunt. One is also given that angles (<BAD) and (<EAC) are congruent. However, in order to prove the triangles (ABC) and (ADE) are congruent (using side-angle-side) congruence theorem, one needs to show that angles (<BAC) and (<DAE) are congruent. An easy way to do so is to write out angles (<BAC) and (<DAE) as the sum of two smaller angles:
<BAC = <BAD + <DAC
<DAE = <DAC + <EAC
Both angles share angle (DAC) in common, since angles (<EAC) and (BAD) are congruent, angles (<BAC) and (<DAE) must also be congruent.
Therefore triangles (ABC) and (ADE) are congruent by side-angle-side, thus sides (BC) and (DE) must also be congruent.
In summary:
AB = AD Given
AC = AE Given
<BAD = <EAC Given
<DAC = <DAC Reflexive
<BAC = <BAD + <DAC Parts-Whole Postulate
<DAE = <EAC + < DAC Parts-Whole Postulate
<BAC = <DAE Transitivity
ABC = ADE Side-Angle-Side
BC = DE Corresponding parts of congruent triangles are congruent
Answer:
1/10
Step-by-step explanation:
You can convert a percentage to a fraction by dividing it by 100%.
__
10% = 10%/100% = 10/100 = 1/10
The slope of the road is 1/10.