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Hunter-Best [27]

4 years ago

5

Factor k 2 + 8k + 15. (k + 1)(k + 15) (k + 8)(k + 7) (k + 3)(k + 5)

1 answer:

Lisa [10]4 years ago

4 0

K² + 8k + 15
k² + 5k + 3k + 15
k(k) + k(5) + 3(k) + 3(5)
k(k + 5) + 3(k + 5)
(k + 3)(k + 5)
The answer is D.

      3x +   4
2x + 5|6x² + 23x + 20
   6x² + 15x
      8x + 20
      8x + 20
      0
The answer is C.

(5d² + 4d - 3) - (3d² - 2d + 4)
(5d² - 3d²) + (4d + 2d) + (-3 - 4)
2d² + 6d - 7
The answer is B.

4b² - 9
4b² + 6b - 6b - 9
2b(2b) + 2b(3) - 3(2b) - 3(3)
2b(2b + 3) - 3(2b + 3)
(2b - 3)(2b + 3)
The answer is C.

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Roger Waters can scrape up just enough money to rent a canoe for 1 hour and 30 minutes. If he paddles out on a lake at 4 kph and

exis [7]

Answer:

He will have paddled the canoe for 4 km.

a. The distance paddled out is equal to the distance paddled returning.

Step-by-step explanation:

Let <em>d </em>be the distance that Roger Waters paddled out.

Let <em>t </em>be the time for the travel he paddled out and <em>t' </em>be the time for returning.

Then from the formula $time=\frac{distance}{speed}$ ,

<em>t </em>= $\frac{d}{4}$ and <em>t' </em>= $\frac{d}{2}$

Total time for the journey = 1 hour 30 minutes = 1.5 hours

So, <em>t</em> + <em>t'</em> = 1.5

$\frac{d}{4} +\frac{d}{2} =1.5$

$\frac{3d}{4} =1.5$

3<em>d</em> = 6

<em>d</em> = 2 km

The total distance he will have paddled the canoe = 2<em>d</em> = 2(2) = 4 km.

Clearly, the distance he paddled out = the distance he returned.

Hence, the correct option is A.

5 0

3 years ago

Read 2 more answers

The first three terms of a geometric sequence are as follows. -256, -64, -16. Find the next two terms of this sequence. Give exa

umka2103 [35]

Hi,

The next two are:

$- 16 \div 4 = - 4 \\ - 4 \div 4 = - 1$

Answer: -4 and -1

Hope this helps.
r3t40

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=1%20%2B%20%20%5Cfrac%7Bm%7D%7B3%7D%20%20%5Cleqslant%206" id="TexFormula1" title="1 + \frac{m}

Katena32 [7]

I think it is m≤15!!

6 0

3 years ago

Solve 1/3 x = -4/5????

nlexa [21]

Answer: X= -12/5

welcome

3 0

3 years ago

Read 2 more answers

A student says that the graph of the equation y = 3(x + 8) is the same as the graph of y = 3x, only translated upwards by 8 unit

Wittaler [7]

Given:

A student says that the graph of the equation $y = 3(x + 8)$ is the same as the graph of $y = 3x$ , only translated upwards by 8 units.

To find:

Whether the student is correct or not.

Solution:

Initial equation is

$y=3x$

$f(x)=3x$

Equation of after transformation is

$y=3(x+8)$

$g(x)=3(x+8)$

Now,

$g(x)=f(x+8)$ ...(i)

The translation is defined as

$g(x)=f(x+a)+b$ ...(ii)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

From (i) and (ii), we get

$a=8\text{ and }b=0$

Therefore, the graph of $y=3x$ translated left by 8 units. Hence, the student is wrong.

8 0

3 years ago