Ask question

Ask question

All categories

stealth61 [152]

2 years ago

14

State what additional information is required in order to know that the triangles are congruent

1 answer:

AleksandrR [38]2 years ago

5 0

17 && 19 are both congruent.

You might be interested in

The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .

sammy [17]

Answer:

$32,24,18,\frac{27}{2} ,\frac{81}{8}$

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is $32,x,y,z,\frac{81}{8}$

Recall that term of a geometric sequence are generally in the form:

$a,ar,ar^2,ar^3,ar^4$

This implies that:

a=32 and $ar^4=\frac{81}{8}$

Substitute a=32 and solve for r.

$32r^3=\frac{81}{8}$

$r^4=\frac{81}{256}$

Take the fourth root to get:

$r=\sqrt[4]{\frac{81}{256} }$

$r=\frac{3}{4}$

Therefore $x=32*\frac{3}{4} =24$

$y=24*\frac{3}{4} =18$

$z=18*\frac{3}{4} =\frac{27}{2}$

8 0

2 years ago

What is the approximate area of a circle with a diameter of 50 centimeters? use π ≈ 3.14. 87.9 square centimeters 379.9 square c

zheka24 [161]

A=πr^2
The answer is 1962.5

6 0

2 years ago

Aliyah had some candy to give to her four children. She first took ten pieces for herself and then evenly divided the rest among

9966 [12]

Answer:

Step-by-step explanation:

Each child received two pieces.

So total pieces received by 4 children = 4*2 = 8

Total pieces = 10 + 8 = 18

3 0

2 years ago

Read 2 more answers

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

2 years ago

Newton’s law of universal gravitation, F=Gm1m2/r²,measures the force of gravity between two masses m1 and m2,where r is the dist

Pavel [41]

Answer:

$G=\frac{Fr^2}{m_1m_2}$

Step-by-step explanation:

Since our equation is $F=\frac{Gm_1m_2}{r^2}$ and we want to solve for G, first we divide both sides by the product $m_1m_2$ , which gives:

$\frac{F}{m_1m_2}=\frac{Gm_1m_2}{m_1m_2r^2}=\frac{G}{r^2}$

So we are left with:

$\frac{F}{m_1m_2}=\frac{G}{r^2}$

Now we multiply both sides by $r^2$ , which gives:

$\frac{Fr^2}{m_1m_2}=\frac{Gr^2}{r^2}=G$

Which gives us our final formula:

$G=\frac{Fr^2}{m_1m_2}$

6 0

2 years ago