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Sonbull [250]
3 years ago
6

What is the result when you change the line y = 6/5 x + 2 to Ax + By + C = 0 form?

Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer:

14x+7y=-214x+7y=−2

Step-by-step explanation:

I think that can help :) wanna chat add me as  friend

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Hi please help me with this i’ll give brainliest if you give a correct and show your work!
Tatiana [17]
1. (1.35)x(.42)

1.35
x. .42
________
270
5400
________
.5670

You need to have the total number of decimal places from the original two numbers. 1.35 has two decimal places and .42 has to decimal places you have a total of four decimal places, Which means 5670 is .5670

2. (.22)x(.04)

.22
x. .04
_______
88
00
_______
.0088

you need to have the total number of decimal places from the original Two numbers. So .22 is two decimal places and .04 is two decimal places, so you will need to have for decimal places. That means that the answer 88 needs to be translated into .0088
6 0
3 years ago
Solve for H<br><br> 19+4H=1-5H
Jobisdone [24]
19=1-5h-4h
19-1=-5h-4h
18=-9h
18/-9=h
h=-0.5
7 0
3 years ago
a carpet cleaning service charges a one-time service fee of $100 with an additional $15 per hour for their business. write a lin
Annette [7]

Answer:

The answer is y= 100 +15x

Step-by-step explanation:

You start with a service fee of $100

$15 per hour

x because the amount of hours can vary

y which is the total cost

y= 100+ 15x

4 0
2 years ago
Hello! I’m struggling with this question just if someone could help me!
valina [46]

Answer: 44sq

Step-by-step explanation:

Trust me :)

8 0
3 years ago
Read 2 more answers
(35 POINTS!!) Based on the graph of the trigonometric functions f (θ) = 4sin θ + 1 and g (θ) = cos 2θ, at
Mashcka [7]

The values on the interval [0, 2π) that makes f (θ) equal to g(θ) is; A: 0, π

<h3>How to solve Trigonometric Functions?</h3>

We are given the trigonometric functions;

f(θ) = 4sin θ + 1

g(θ) = cos 2θ

We know from trigonometric identities that;

cos 2θ = 1 - 2sin²θ

At f(θ) = g(θ), we have;

4sin θ + 1 = 1 - 2sin²θ

2sin²θ + 4sin θ = 0

2sinθ(sin θ + 2) = 0

2sinθ = 0

θ = sin⁻¹(0/2)

θ = 0, π

Read more about Trigonometric Functions at; brainly.com/question/6904750

#SPJ1

7 0
2 years ago
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