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Valentin [98]
3 years ago
7

X + 2y = 8 X + 3y = 12

Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

(0,4)

Step-by-step explanation:

Subtract the first equation from the second, obtaining y = 4.  Then substitute 4 for y in the first equation, obtaining x + 2(4) = 8; it follows that x = 0.

The solution is (0,4).

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Solve |z - 8| = 4 please
bezimeni [28]

Answer:

4

Step-by-step explanation:


5 0
3 years ago
3. Find the slope of the line<br> f(x)1/2x+8. Describe how the line slopes.
wariber [46]

Answer:

slope: \frac{1}{2}

Step-by-step explanation:

f(x)=mx+b\\m=slope\\\\f(x)=\frac{1}{2} x+8\\\frac{(rise)}{(run)}=\frac{1}{2}

the linear line has a positive slope that goes up by 1 unit and right by 2 units

7 0
2 years ago
Cna i get some help with dis plz
Tomtit [17]

Let b_1,b_2,\ldots,b_{20} be the 20 marks of the boys, and g_1,g_2,\ldots,g_{10} be the 10 marks of the girls.

We know that the global mean was 70, meaning that

\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100

By the same logic, we work with the marks of the boys alone: we know the average:

\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62

And we deduce the sum of the marks for the boys:

b_1+b_2+\ldots+b_{20}=1240

Which implies that the sum of the marks of the girls is 2100-1240=860

And finally, the mean for the girls alone is

\dfrac{860}{10}=86

6 0
2 years ago
Lina had a 1 liter carton of milk. She poured 748 milliliters into cups for her
-BARSIC- [3]
the answer would be 1,748 i’m pretty sure if not i’m so sorry
5 0
2 years ago
Read 2 more answers
I have two fair dice each numbered 1 to 6 I throw both dice and add the two numbers together. What is the probability that the n
liraira [26]

Answer:

7 / 36

Step-by-step explanation:

Using the sample space attached,

Required outcome = multiple of 5 from the sun of two rolled dice = 7

Total possible outcomes =(number of faces)² = 6² = 36

Therefore, the probability of obtaining a sum which is a multiple of 5 is :

P(sum which is a multiple of 5) :

Required outcome / Total possible outcomes

= 7 / 36

8 0
2 years ago
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