How to use inverse cosin

Please answer all of them and show your work please!

sattari [20]

Answer:

br=uh

Step-by-step explanation:

u need our help 4 this homework? Just do it yourself, though i would do this for 270 points.

3 0

2 years ago

Read 2 more answers

Find the missing side of the triangle

Thepotemich [5.8K]

I dont know the answer lol but imma say B

4 0

3 years ago

PLSSSSS HELPPP solve for x, round to nearest tenth

inessss [21]

Answer:

17.6

Step-by-step explanation:

7 0

2 years ago

Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are relat

anzhelika [568]

Answer:

(c) Probability that a failure is due to loose keys = 0.2376

(d) Probability that a failure is due to improperly connected or poorly welded wires = 0.078

Step-by-step explanation:

The Whole probability scenario is given for Computer Keyboard failures.

(a) Let F be the event of failure due to faulty electrical connects, P(F) = 0.12

M be the event of failure due to mechanical defects, P(M) = 0.88

LK be the event of mechanical defect due to loose keys, P(LK/M) = 0.27

IA be the event of mechanical defect due to improper assembly, P(IA/M) =0.73

DW be the event of electrical connects due to defective wires,P(DW/F) = 0.35

IC be the event of electrical connects due to improper connections,

P(IC/F) = 0.13 .

PWW be the event of electrical connects due to poorly welded wires,

P(PWW/F) = 0.52

(b) Keyboard failures

Faulty electrical connects Mechanical Defects

P(F) = 0.12 P(M) = 0.88

Defective wires Improper Poorly Loose Keys Improper

P(DW/F)=0.35 Connections Welded wires P(LK/M)=0.27 Assembly

P(IC/F)=0.13 P(PWW/F)=0.52 P(IA/M)=0.73

This is the required tree diagram.

(c) Probability that a failure is due to loose keys is given by:

P(LK) =P(LK/M) * P(M) {This means mechanical failure is due to loose

keys}

P(LK) = 0.27 * 0.88 = 0.2376 .

(d) Probability that a failure is due to improperly connected or poorly welded

wires is given by P(IC $\bigcup$ PWW) ;

P(IC $\bigcup$ PWW) = P(IC) + P(PWW) - P(IC $\bigcap$ PWW) { Here P(IC $\bigcap$ PWW) = 0 }

P(IC) = P(IC/F) * P(F) = 0.13 * 0.12 = 0.0156

P(PWW) = P(PWW/F) * P(F) = 0.52 * 0.13 = 0.0676

Therefore, P(IC $\bigcup$ PWW) = 0.0156 + 0.0676 - 0 = 0.078 .

8 0

3 years ago

Cynthia Besch wants to buy a rug for a room that is 1919 ft wide and 2727 ft long. She wants to leave a uniform strip of floor a

yulyashka [42]

Answer:

The dimension of the rug would be 17 ft × 9 ft.

Step-by-step explanation:

Given

length of the room = 27 ft.

width of the room = 19 ft.

suppose, she leaves a uniform strip of x ft. around the rug.

So,

The length of rug = (27-2x)ft.

Width of rug= (19-2x)ft.

∴ Area of the rug= length×width

$= (27-2x)(19-2x)$

$= 513-54x-38x+4x^2$

$= 513-92x+4x^2$

According to the question,

$513-92x+4x^2=153$

$513-92x+4x^2-153=0$ ( subtract 153 both sides)

$4x^2-92x+360=0$

$4(x^2-23x+90)=0$

$x^2-23x+90=0$

$x^2-(18+5)x+90=0$ ( Middle term splitting)

$x^2-18x-5x+90=0$

$x(x-18)-5(x-18)=0$

$(x-5)(x-18)=0$

$x-5=0$ or $x-18=0$ ( zero product property)

$x=5$ or $x=18$

if x=18, dimension would be negative ( Not possible)

Thus, x= 5

Hence,

length of rug= 27-10=17 ft.

width of rug= 19-10=9 ft.

8 0

3 years ago