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4 years ago

23. If XY = 13, XA = 4, and XZ = 26, then XB =

Mathematics

1 answer:

UkoKoshka [18]4 years ago

5 0

Answer:

It is given that in triangle XYZ, XY = 13, YZ=20, and XZ=25.Using the law of cosines, we have

CosC=\frac{a^2+b^2-c^2}{2ab}

cosZ=\frac{(YZ)^2+(XZ)^2-(XY)^2}{2(YZ)(XZ)}

CosZ=\frac{(20)^2+(25)^2-(13)^2}{2(20)(25)}

CosZ=\frac{400+625-169}{1000}

CosZ=\frac{856}{1000}

CosZ=0.856

Z=cos^{-1}(0.856)

Z=37.13^{\circ}

Step-by-step explanation:

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23. If XY = 13, XA = 4, and XZ = 26, then XB =​

23. If XY = 13, XA = 4, and XZ = 26, then XB =