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oksano4ka [1.4K]
3 years ago
7

How do you know if something is linear

Mathematics
2 answers:
alukav5142 [94]3 years ago
3 0

when an  equation between two variables that gives a straight line when plotted on a graph

Hatshy [7]3 years ago
3 0

If the equation has an x^2 or x^3 or anything other than just numbers and x's, then it is NOT linear. a linear equation is of the form:  

y=mx+b

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The function f is continuous on the closed interval [1,15] and has the values shown on the table above. Let g(x) = ∫f(t) dt [1,x
Anna11 [10]
We're looking for the two values being subtracted here. One of these values is easy to find:

<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
 
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:

</span><span>Each integral breaks down like so:

(3-1)*f(1)=4

(6-3)*f(3)=9

(10-6)*f(6)=16

(15-10)*f(10)=10.

So, the sum of all these integrals is 39, which means g(15)=39.
 
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
3 0
3 years ago
Read 2 more answers
How is the graph of y=x^2 different from the graph of y=x^2-2
Zinaida [17]
It is two units shifted downwards. you can see it by substituting x=0 for both equations
5 0
3 years ago
Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri
Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after \frac{640}{7} miles

Step-by-step explanation:

Given

The table represents the car mileage

y = -\frac{1}{5}x + 31 --- The van

First, calculate the car's slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

From the table, we have:

(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)

So, we have:

m = \frac{10.5 - 13.5}{180 - 60}

m = \frac{-3}{120}

m = -\frac{1}{40}

Calculate the equation using:

y = -\frac{1}{40}(x - 60)+13.5

y = -\frac{1}{40}x + 1.5+13.5

y = -\frac{1}{40}x + 15

m = -\frac{1}{40} implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

y = -\frac{1}{5}x + 31 --- The van

By comparison to: y = mx + b

m = -\frac{1}{5}

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

1/40 < 1/5

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

y = -\frac{1}{5}x + 31 --- The van

y = -\frac{1}{40}x + 15 --- The car

Equate both

-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15

Collect like terms

\frac{1}{40}x -\frac{1}{5}x  =-31 + 15

\frac{1}{40}x -\frac{1}{5}x  =-16

Take LCM

\frac{x - 8x}{40} = -16

\frac{- 7x}{40} = -16

Solve for -7x

-7x = -640

Solve for x

x = \frac{640}{7}

5 0
3 years ago
At what point does the line given by the following equation cross the y-axis?
QveST [7]
Pretty sure the answer is D:

Because the equation is in the format y=mx+c (c being the y intercept), we know that the y intercept (or where the line will cross the y axis) will be -9.

B also says -9 but we have to be careful because it states that the x axis is -9 rather than the y axis.

Hope that helped you understand.
4 0
3 years ago
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Guys help me!<br><br> 1. What is the domain and range? Help plsss!
Valentin [98]
Range is the highest value minus the lowest value
6 0
3 years ago
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