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Veronika [31]
3 years ago
8

Find the circumference of the circle. Use π=3.14

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

There is no picture or diameter/radius measurements, therefore this question cannot be answered properly.

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Adequate Preparation for Retirement. In 2018, RAND Corporation researchers found that 71% of all individuals ages 66 to 69 are a
Svetllana [295]

Answer:

A - Hopes this helps.

Step-by-step explanation:

4 0
3 years ago
Which expression is equivalent to 7.2 x 7.2 x 7.2 ?
Sladkaya [172]

Answer:

7.2^3 or 7.2 cubed=373.248

4 0
3 years ago
Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

                                                                   =  \frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}

                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
4 years ago
Read 2 more answers
BC = x + 14, AB = x + 10, AC = 22
irinina [24]

ab = x + 10 \\  bc = x  + 14 \\ ac = 22  \\ (x + 10) + (x + 14) = 22 \\ x + x + 10 + 14 = 22 \\ 2x + 24 = 22 \\ 2x = 22 - 24  \\ 2x =  - 2 \\ x =  \frac{ -2}{2}  \\ x =  - 1

4 0
3 years ago
What is the length x of the right triangle, rounded to the nearest<br> tenth?
Zarrin [17]

Answer:

109.5; B

Step-by-step explanation:

From your identity,

CosA = adjacent/ hypothenus

A represent an arbitrary angle between the sides in question.

In the question above, A=64

Hypothenus is the longest side and adjacent is the side just below the angle .

In the above case,

Hypothenus= X

adjacent =48

This means;

Cos64 = 48 /X

X = 48 / cos64; [ from cross multiplication and diving through by cos64]

X = 48 /0.4383 [ cos64 in radian = 0.4383]

= 109.51

= 109.5 to the nearest tenth.

Note( do your calculation of angle in radian or else, you won't get the answer)

6 0
3 years ago
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