Cm wait what is the question
1) first pick red 5/9 blue 4/9
2) second pick when red has been picked red now becomes 4/8, blue stays 4/8
2) Second pick when blue has been picked blue now becomes 3/8, red stays 5/8
Mind you, you only need both different colours so:
first pick red 5/9 x sec pick blue 4/8 = 20/72
and first pick blue 4/9 x sec pick red 5/8 = 20/72
add both up 20/72 + 20/72 = 40/72 = 5/9
<h2><u>EQUATION</u></h2><h3>Exercise</h3>
2(3 + 3y) + y = 11
First, apply the distributive property:
2(3 + 3y) + y = 11
6 + 6y + y = 11
6 + 7y = 11
Substract 6 from both sides:
6 - 6 + 7y = 11 - 6
7y = 5
Divide both sides by 7:


<h3><u>Answer</u>. The value of y = 5/7.</h3>