Question

(3y-2)/3+(2y+3)/3=(y+7)/6 step by step plz

Answer 1

After solving the expression $\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}$ the value of y is $y=\frac{5}{9}$

Step-by-step explanation:

We need to solve the expression $\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}$ to find value of y

Solving:

$\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}$

Taking LCM of 3,3 and 6 is 6

Multiply all terms by 6

$\frac{3y-2}{3}*6+\frac{2y+3}{3}*6=\frac{y+7}{6}*6\\(3y-2)*2+(2y+3)*2=y+7$

Simplifying:

$6y-4+4y+6=y+7$

Combining like terms:

$6y+4y+6-4=y+7\\10y+2=y+7$

Simplifying to find value of y:

$10y-y=7-2\\9y=5\\y=\frac{5}{9}$

So, after solving the expression $\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}$ the value of y is $y=\frac{5}{9}$

Keywords: Solving Fractions

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