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MatroZZZ [7]
2 years ago
13

I am in need of assistance

Mathematics
1 answer:
vivado [14]2 years ago
3 0

1. To find the x-intercept, replace y in the equation with 0, then solve for x.

... To find the y-intercept, replace x in the equation with 0, then solve for y.

If the equation is easily put into the form

... x/a + y/b = 1

Then the x-intercept is "a" and the y-intercept is "b".

2. Let's graph 3x+4y = -12.

If we divide the equation by -12, we can put it into the form

.. x/(-4) + y/(-3) = 1

This equation has x-intercept -4 and y-intercept -3.

(If you know the intercepts, you can simply draw the line through them to graph your linear equation.)

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Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

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3 years ago
What is the length of the hypotenuse for a right triangle with legs of length 9 and 40? A) 41 B) 43 C) 45 D) 47
Katena32 [7]

Answer:

A) 41

Step-by-step explanation:

Let the hypotenuse be denoted by h

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h =  \sqrt{1600 + 81}  =  \sqrt{1681}

h = 41

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butalik [34]

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