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Firlakuza [10]
3 years ago
14

What’s the answer to this question

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Area Formula:

a + b  \times .5 \times h

7+10.4 x .5 x 6.7

Answer: 58.29

I hope this is right!

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Guys pls helpppppp me I need help ​
attashe74 [19]

Answer:what grade is this?

Step-by-step explanation:

6 0
3 years ago
Find the distance between (1,2) and (5,5).
masha68 [24]

Answer: 5

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

3 0
3 years ago
8^2 + b^2 = 10^2<br> what is b?<br> HELP HELP FAST
vodka [1.7K]

Answer:

2

Step-by-step explanation:

10^2 - 8^2 = B^2

B = 2

3 0
4 years ago
Read 2 more answers
Two last help with math please and thanks!
12345 [234]
1st problem:
Use the Pythagorean theorem:
a^2+b^2=c^2
49+361=c^2
c^2=410
c=20.24
The answer is 20m

2nd problem:
First calculate the height using the Pythagorean theorem:
a^2+b^2=c^2
20^2+b^2=625     (i got 20 {radius} by half-ing the base edge length)
400+b^2=625
b^2=225
b=15

Next, solve for the volume:
V=a^2*h/3
V=40^2*15/3
V=1600*5
V=8000

The answer is the second choice or B.

5 0
4 years ago
Read 2 more answers
Andrew is flying a kite at a height of 120ft. While the wind is carrying the kite horizontally away from her at the rate of 24ft
Paha777 [63]

Answer:

The string of the kite is being let out at the rate of 19.2 ft/sec.

Step-by-step explanation:

See the diagram attached.

The vertical height (BK) of the kite is 120 ft.

The kite string is of length (AK) of 200 ft.

Therefore, the horizontal distance (AB) from Andrew to kite is = \sqrt{200^{2} - 120^{2}}  = 160 ft.  

Now, applying the Pythagoras Theorem,

AB² + BK² = AK²

⇒ l² + h² = s² {Where, l is the horizontal length, h is the height and s is the string length}

Differentiating with respect to time t both sides

2l\frac{dl}{dt} + 0 = 2s\frac{ds}{dt} {Since, height of kite is constant}

⇒ 2 \times 160 \times 24 = 2 \times 200 \times \frac{ds}{dt}

⇒\frac{ds}{dt} = 19.2 ft per sec.

Therefore, when the wind is carrying the kite horizontally at the rate of 24 ft/sec, then the string of the kite is being let out at the rate of 19.2 ft/sec. (Answer)

3 0
3 years ago
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