<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
Step-by-step explanation:
You need to find out how many cabinets it is
Answer:
A drawing. I guess the sky
Step-by-step explanation:
this is a very hard question
Answer:
x = 15°
Step-by-step explanation:
Complementary angles are two angles whose sum = 90°
∠A + ∠B = 90°
3x + 45 = 90
3x = 45
x = 45/3
x = 15°
If you would graph the triangle, one of the legs would be 8 and another would be 5 and the area of a triangle is bxh/2 so the equation is 8x5/2=20un².
Hope this helped! :)