Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
M<7 + m<8 + m<9 = m<EAD
31 + 22 + m<9 = 102
53 + m<9 = 102
m<9 = 49
Answer:
nca - gru is the correct answer
Step-by-step explanation:
Answer:
The correct answer would be A) (4, 49.6)
Step-by-step explanation:
In order to find the equation, we first have to start with the base form of direct variation.
y = kx
Now we input the k value.
y = 12.4x
Now that we have this, we can try the ordered pairs and look for which satisfies the equation.
y = 12.4x
49.4 = 12.4(4)
49.4 = 49.4
Since this is the true statement, this is the ordered pair that works.
