If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Answer:
10.8 cm
Step-by-step explanation:
Using cosine law
g² = 7.1² + 6.7² - 2(7.1)(6.7)cos(103)
g² = 116.7018433
g = 10.80286274
<u>Answer:</u>
- Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.
<u>Step-by-step explanation:</u>
We know that:
- 48 + 8(b) = Carly's expenditure
- 10(b) = Carly's expenditure
- 48 + 8b = 10b
- B = Boxes of cards
<u>Work:</u>
- 48 + 8b = 10b
- => 48 + 8b - 8b = 10b - 8b
- => 48 = 2b
- => b = 24
<u>Now, let's substitute the value of b into any equation.</u>
<u>Hence, Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.</u>
Hoped this helped.
Answer:
you need to draw a triangle of given dimensions
Step-by-step explanation:
if B is right angle triangle then you can assume that either AB or BC is base and other one is perpendicular. So that makes AC hypotenuse
so let's assume BC is base of 6 cm. so draw a base of 6 cm line , name it BC
then draw a 90 degree angle on B keeping BC as Base . now length of perpendicular would be 4.5 cm. this perpendicular would be AB
no join A and C . length of AC should be 7.5 cm. if it's not then something is wrong in given question.