All categories

3 years ago

you are dividing 3972 by 41 explain why the first digit in the quotient should be placed over the tens place of the dividend

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

5 0

41)3972...since 41>39 you won't have the first digit of the quotient in the

Paladinen [302]3 years ago

4 0

Answer:

We have to divide 3972 by 41.

This means that 3972 is the dividend and 41 is the divisor.

When we start dividing the dividend by the divisor the first digit in the quotient is placed over the tens place of the dividend since 41 is greater than 39 so, we have to take one more digit of the dividend so that it could be divisible by 41.

i..e we have to firstly consider 397 and see which multiple of 41 is smaller or equal to 397.

You might be interested in

Plssss help asap 10 points

BartSMP [9]

Here is a link of math

bit.^{} ly/3fcEdSx

www.mathpapa.com

Hope it's helpful :)

5 0

2 years ago

What is expanded form of 605,970

Luba_88 [7]

605,970 is expanded in this form:

(6 x 100,000) + (0 x 10,000) + (5 x 1,000) + (9 x 100) + (7 x 10) + (0 x1)

each number is multiplied to the corresponding place value.
6 is on the one hundred thousand place value
0 is on the ten thousand place value
5 is on the one thousand place value
9 is on the hundreds place value
7 is on the tens place value
0 is on the ones place value

OR

600,000 + 5,000 + 900 + 70 = 605,970

4 0

2 years ago

Read 2 more answers

Explain how to write 3*3/8 as the product of a whole number and a unit fraction

Lady_Fox [76]

9/8 because you multiply 3 × 3 and leave the denominator the same

4 0

2 years ago

Solve for x using the quadratic formula x^2-6x +9=0

Rufina [12.5K]

Answer:

3 both ways x = 3

EXPLANATION:

plug in inputs and do a little simplifying we get

x = 6 ± √(36-36) all of that over 2

So we simplify and we get 6±sqrt(0) / 2

Then we get 6/2 = 3

x-0 = x+0

thats why there is only one answer

4 0

2 years ago

Read 2 more answers

Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg

Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let X = number of college women on a diet.

The probability of a woman being on diet is, P (X) = p = 0.70.

The sample of women selected is, n = 267.

The random variable thus follows a Binomial distribution with parameters n = 267 and p = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions ( $\hat p$ ) follows a Normal distribution.

The mean of this distribution is:

$\mu_{\hat p} = p = 0.70$

The standard deviation of this distribution is: $\sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028$

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

$P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z$

**Use the z-table for the probability.

$P(\hat p \geq 0.75)=1-P(Z$

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0

2 years ago