All categories

3 years ago

Divide please 5⁄7 ÷ 2⁄7

Mathematics

2 answers:

JulijaS [17]3 years ago

8 0

35/14

5/2

keep switch flip

RSB [31]3 years ago

7 0

Answer:

Step-by-step explanation:

57÷27=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

57×72=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

5×77×2=3514

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 35 and 14 using

GCF(35,14) = 7

35÷714÷7=52

The fraction

is the same as

5÷2

Convert to a mixed number using

long division for 5 ÷ 2 = 2R1, so

52=212

Therefore:

57÷27=21/2

You might be interested in

The 10th term of an arithmetic sequence is 10 and the sum of the first 10 terms is -35. Find the first term a1, and the common d

lina2011 [118]

The first term is − 17 and the common difference is 3

8 0

3 years ago

How to simplify 2a³ × a⁴

quester [9]

Add the exponents since it’s multiplication, so it would be 2a^7, hope this helps

6 0

3 years ago

Read 2 more answers

The price of a technology stock was $9.74 yesterday. Today, the price fell to $9.67. Find the percentage decrease. Round your an

agasfer [191]

% change = (new value - old value)/(old value) * 100%
.. = (9.67 -9.74)/9.74 * 100%
.. = -0.07/9.74 * 100%
.. = -0.7%

The decrease is 0.7%.

5 0

3 years ago

Plzzzzzzz helpppp right answer gets brainly

Citrus2011 [14]

Answer:

Algebra I believe

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Given A(2, 3) B(1, 4) C(1, 3) D(-2, 2). How are AB and CD related?

kondaur [170]

The vector AB is not related with the vector CD as k is not the same for each pair of components.

<h3>Are two vectors similar?</h3>

In this question we must prove if the vector AB is a multiple of the vector CD, that is:

$\overrightarrow{AB} = k \cdot \overrightarrow {CD}$

$\vec B - \vec A = k \cdot [\vec D - \vec C]$

(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]

(- 1, 1) = k · (- 3, - 1)

Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.

To learn more on vectors: brainly.com/question/13322477

#SPJ1

3 0

2 years ago