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kobusy [5.1K]
3 years ago
9

What is -a^-2 if a=-5

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0
-a^{-2}=-(-5)^{-2}=-\left(\dfrac{1}{-5}\right)^2=-\dfrac{1}{25}
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Check 8.0622577483 rounded to the nearest tenth <br> = 8.1 <br> Is that correct
alisha [4.7K]
Yes that it's correct because numbers that are 5+ round up and numbers that are 4-stay the same.
6 0
3 years ago
Read 2 more answers
What is the answer to |x-4|&lt;13
VARVARA [1.3K]

Answer:

<h2>The solution is -9 < x < 17.</h2>

Step-by-step explanation:

|x-4|<13.

The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.

Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.

7 0
3 years ago
The equation of a parabola is shown.
WARRIOR [948]
The axis of symmetry for this parabola is the x-axis. The general form of the equation is:
4p(x-h) = (y-k)^2
where the focus has the coordinates of (h+p,k)

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4(1/3)(x-7)^2 = (y - 0)^2

Therefore the coordinates of the focus is:
(7+(1/3),0)

The answer is A.) (71/3,0)


5 0
3 years ago
Need help, what is the answer???
IRISSAK [1]

Answer:

9

Step-by-step explanation:

3 0
3 years ago
I need help on #10
Ede4ka [16]
D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)

Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
6 0
3 years ago
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