Y = 500(1 + r)^x; where r is the rate and x is the number of years.
500(1 + r)^2 = 551.25
(1 + r)^2 = 551.25/500 = 1.1025
1 + r = sqrt(1.1025) = 1.05
Therefore, the equation that represents y, the value of the item after x years is
y = 500(1.05)^x
Answer:
100x+120y = z
z= $ 63000
Step-by-step explanation:
Product Welding Assembly Painting Cont. to profit
X 2x hours 3x hours 1xhour = $100x
Y 3y hours 2y hours 1y hour = $120y
<u> </u>
Total hours 1500 hours 1500 hours 550 hours
available
Let X represent product X
Let Y represent Product Y
2x + 3y = 1500
x + y = 550
y= 550-x
2x + 3(550-x) = 1500
2x + 1650- 3x = 1500
150 = x
y = 550-150
y = 400
Objective Function Z = 100x + 120y
Z = 100(150) + 120( 400)
Z = 15000+48000
Z = $63000
Answer:
radical
Step-by-step explanation:
Answer:
105 boys
Step-by-step explanation:
At a local preschool there is a ratio of 3 boys to 4 girls.
i.e boys:girls = 3:4
There are 245 preschoolers enrolled.
Number of boys = 
× 245 = 105 boys
