Answer:
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
Step-by-step explanation:
Remember that:
- Two lines are parallel if their slopes are equivalent.
- Two lines are perpendicular if their slopes are negative reciprocals of each other.
- And two lines are neither if neither of the two cases above apply.
So, let's find the slope of each equation.
The first basketball is modeled by:

We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:

And divide both sides by four:

So, the slope of the first basketball is -3/4.
The second basketball is modeled by:

Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:

And divide both sides by negative eight:

So, the slope of the second basketball is also -3/4.
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
56/8=7. so we multiply 7 by 7.7*7=49; the helicopter is 49 in. wide
Solve for one of the variables in the first equation (in this case, I will solve for X):
X = Y + 3
Then use that value of X in the second equation to solve for Y:
X + 3Y = 9
(Y + 3) + 3Y = 9
4Y + 3 = 9
4Y = 6
Y = 1.5
Use the value of Y we just found in the X equation we created:
X = Y + 3
X = 1.5 + 3
X = 4.5
Therefore X = 4.5 or 9/2 and Y = 1.5 or 3/2.
If the triangles are similar, the proportion of the legs on the left to the legs on the right will be equal. This proportion would look like:

(You needed to combine the orange segment and the yellow segment to find the total length of the large triangle).
Now, cross multiply and solve for x:
28x+14=30x
<em>*Subtract 28x from both sides to isolate the variable*</em>
14=2x
<em>*Divide both sides by 2*</em>
7=x
Hope this helps!!