Answer:
c
Step-by-step explanation:
c. j = a + 5
such that 7 = 2 +5
Answer:
we need to prove : for every integer n>1, the number
is a multiple of 5.
1) check divisibility for n=1,
(divisible)
2) Assume that
is divisible by 5, 
3) Induction,



Now, 



Take out the common factor,
(divisible by 5)
add both the sides by f(k)

We have proved that difference between
and
is divisible by 5.
so, our assumption in step 2 is correct.
Since
is divisible by 5, then
must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number
is a multiple of 5.
Answer:
- 1.67
Step-by-step explanation:
f(x) =
- 
=
- 
=
- 2
= - 1 
= -1.6666666
= -1.67
Adults = 9
Children = 2
Let x be the number of adults.
11-x is the number of children.
22x + 15(11-x) = 228
22x + 165 - 15x = 228
22x - 15x = 228 - 165
7x = 63
7x / 7 = 63 / 7
x = 9 number of adults.
11 - x = 11 - 9 = 2 number of children.
To check:
22x + 15(11-x) = 228
22(9) + 15(11-9) = 228
198 + 30 = 228
228 = 228
(not my answer btw)