Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Answer:
16 cups of flour
Step-by-step explanation:
Y= -2x²-3x+2, (form y = ax² +b .x + c
The parabola opens downward & hence it's Vertex is a MAXIMUM.
We know that the axis of symmetry is -b/2a ==>3/(-4) ==>
x= - 3/4 (axis of symmetry. At x=-3/4 , y = 25/8 = 3.125
Hence the axis of symmetry is x= - 3/4 & the vertex is at (-3/4, 25/8)
I hope this helps you
3t÷3 < -15÷3
t < -5