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tatuchka [14]
3 years ago
12

the area of the region bounded by the curve y=e^2x the x axis the y axis and the line x=2 is equal toA) e^4/2 -e B) e^4/2 - 1 C)

e^4/2 - 1/2 D) 2e^4 -e E) 2e^4 -2

Mathematics
1 answer:
klemol [59]3 years ago
5 0

Answer:b

Step-by-step explanation:

Given

y=e^{2x}

Area bounded by y=e^{2x}, y=0,\ x=0\ and\ x=2 is shown by shaded area in the diagram

Area=A=\int_{0}^{2}ydx

A=\int_{0}^{2}e^{2x}dx

A=\left [ \frac{e^{2x}}{2}\right ]^{2}_{0}

A=\frac{1}{2}\left [ e^4-e^0\right ]

A=\frac{e^4}{2}-1

thus option b is correct

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Perimeter of a rectangular sticker is 26 centimeters. The area is 30 centimeters. What are the dimensions?
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\tt\it\bf\it\huge\bm{\mathfrak{{\red{hello*mate♡}}}}

\tt\it\bf\huge\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{ANSWER==>}}}}

_______________________________

<h2>Given:-</h2>

<h3>perimeter of rectangle=26cm</h3>

<h3>Area of rectangle=>30cm²</h3>

<h3>{•°• perimeter of rectangle=2(l+b) }</h3>

<h3>{•°•. Area of rectangle=lxb}</h3>

<h3>So, 2(l+b)=26</h3><h3> =>(l+b)=26/2</h3><h3> =>l+b=13</h3><h3> =>l=(13-b) ----------(1)</h3>

<h3>Again,</h3>

<h3> =>lxb=30</h3><h3> =>(13-b)xb=30 {putting the value of l from equation 1}</h3><h3> </h3><h3> =>13b-b²=30</h3><h3> =>b²-13b+30=0</h3><h3> =>b²-10b-3b +30=0</h3><h3> =>b(b-10)-3(b-10)=0</h3><h3> =>(b-10)(b-3)=0</h3><h3> </h3><h3>or,</h3>

<h3> =>b=10 or b=3</h3>

<h3>putting the value of b in equation (1)</h3>

<h3> =>l=(13-b)</h3><h3> =>l=13-10=3 { taking b=10}</h3><h3> =>l=13-3=10 { taking b=3}</h3>

<h3>Hence, length=3 when breadth=10</h3><h3> length=10 when breadth=3</h3>

<h3>•take care</h3><h3>°mark as brainlist please</h3><h3>•follow me</h3>

✌️✌️

_______________________________

\tt\it\bf\huge\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{BE-BRAINLY !}}}}

5 0
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