Answer:
okay
Step-by-step explanation:
By definition of absolute value,
Differentiating once gives
As
from either side, we find that
, so really
Differentiating again, we find
but this time, the limit does not exist as
from either side, so
is undefined. However, we see that
when
, and
when
, and we know that
is continuous at
. This means the concavity must change at
, so (0, 0) is the inflection point. (The takeaway is that inflection points *can* occur when the second derivative is undefined, but not always.)
1) x^2=64 is the same as x=the root of 64 which gives us: (+-)8
2) here you must us pq-formel as:
5m^2-5m=60
5m^2-5m-60=0
(m^2-5m-60)/5=0
m^2-m-12=0
m=0,5(+-) the root of 0,25+12
m=0,5(+-)3,5
m1=0,5+3,5
m2=0,5-3,5
15) x^2=7x
x^2-7x=0 here there is two x, so:
x(x-7)=0
x1=0
x2=7
<span>
Here you can only use PQ formula in all the others, just as I did in the question number 2</span>
Answer:
the answer is 54 hope this helps lol
Step-by-step explanation:
Also this isnt high school level it's elementary RSM level.