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2 years ago

(sinx) / (1-cosx) =cscx+cotx

1 answer:

7 0

$~~\text{L.H.S}\\\\=\dfrac{\sin x}{1-\cos x}\\\\\\=\dfrac{\sin x(1+ \cos x)}{(1 -\cos x)(1+ \cos x)}\\\\\\=\dfrac{\sin x + \sin x \cos x}{1- \cos^2 x}\\\\\\=\dfrac{\sin x+ \sin x \cos x}{\sin^2 x}\\\\\\=\dfrac{\sin x}{ \sin^2 x}+ \dfrac{\sin x \cos x}{ \sin^2 x}\\\\\\=\dfrac{1}{ \sin x} + \dfrac{\cos x}{ \sin x}\\\\\\=\csc x + \cot x\\\\\\=\text{R.H.S}\\\\\text{Proved.}$

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I need help with 2-51. PLEASEE AND TYYY

tia_tia [17]

Answer:

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Step-by-step explanation:

you get the vertex by making the denominator =0

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so the vertex would be (-5,0)

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3 years ago

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siniylev [52]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0

fomenos

• The value of the discriminant ,D= -16

• The solution to the quadratic equation is

$x=\frac{1+2i}{5}\text{ or }\frac{1-2i}{5}$

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

$x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}$

Note that:

√-1 = i

$x=\frac{2\pm\sqrt[]{16\times-1}}{10}$

$x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}$ $x=\frac{2\pm4i}{10}$ $x=\frac{2}{10}\pm\frac{4i}{10}$ $x=\frac{1}{5}\pm\frac{2}{5}i$ $x=\frac{1\pm2i}{5}$

That is;