Use the following work shown below to answer the following question.

Mathematics

1 answer:

zysi [14]4 years ago

3 0

Answer:

$\frac{3 + \sqrt{3x} }{3 - x}$

Step-by-step explanation:

You can use the work they gave you and continue from there:

$\frac{\sqrt{3}(\sqrt{3}) + \sqrt{3}(\sqrt{x}) }{(\sqrt{3}) ^{2} - (\sqrt{x} )^{2} }$

First, simplify the numerator:

$\frac{3 + \sqrt{3x} }{(\sqrt{3}) ^{2} - (\sqrt{x}) ^{2} }$

Finally, simplify the denominator:

$\frac{3 + \sqrt{3x} }{3 - x}$

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What is x, if the volume of the cylinder is 768pi rcm3?

AVprozaik [17]

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$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=8\\ h=x\\ V=768\pi \end{cases}\implies 768\pi =\pi (8)^2(x)\implies 768\pi =64\pi x \\\\\\ \cfrac{768\pi }{64\pi }=x\implies 12=x$