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ki77a [65]
3 years ago
12

Use the following work shown below to answer the following question.​

Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

\frac{3 + \sqrt{3x} }{3 - x}

Step-by-step explanation:

You can use the work they gave you and continue from there:

\frac{\sqrt{3}(\sqrt{3}) + \sqrt{3}(\sqrt{x})  }{(\sqrt{3}) ^{2} - (\sqrt{x} )^{2} }

First, simplify the numerator:

\frac{3 + \sqrt{3x} }{(\sqrt{3}) ^{2} - (\sqrt{x}) ^{2} }

Finally, simplify the denominator:

\frac{3 + \sqrt{3x} }{3 - x}

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anygoal [31]

Answer:

\sf  y=7\frac{2}{3} and \sf x = \frac{2}{3}

Explanation:

\sf (1)  \  \  (2x+y = 9)

\sf (1) \ \  (2x+5y = 37)

<u>solve for y</u>:

\sf 2x + y = 9

\sf 2x + 5y = 37

-----------------

\sf 0x + 6y = 46

\sf 6y = 46

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<u>solve for x</u>:

\sf 2x + y = 9

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\sf 2x = \frac{4}{3}

\sf x = \frac{2}{3}

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